## Description

**QUESTION:**

Using Cartesian vector analysis, determine the resultant of the three forces about the base of the column at A.

Given:

F_{1} = (F_{1x}i + F_{1y}j + F_{1z}k)

F_{2} = (F_{2x}i + F_{2y}j + F_{2z}k)

F_{3} = (F_{3x}i + F_{3y}j + F_{3z}k)

F_{1x} = 400 N

F_{1y} = 300 N

F_{1x} = 120 N

F_{2x} = 100 N

F_{2y} = – 100 N

F_{2x} = – 60 N

F_{3x} = 0 N

F_{3y} = 0 N

F_{3z} = – 500 N

a = 4 m

b = 8 m

c = 1 m

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